2000Q-0.02(x^2)=0

Solution for 2000Q-0.02(x^2)=0 equation:

2000-0.02(Q^2)=0

a = -0.02; b = 0; c = +2000;
Δ = b2-4ac
Δ = 02-4·(-0.02)·2000
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$Q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*-0.02}=\frac{0-4\sqrt{10}}{-0.04}
=-\frac{4\sqrt{10}}{-0.04}
=-\frac{\sqrt{10}}{-0.01}
$
$Q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*-0.02}=\frac{0+4\sqrt{10}}{-0.04}
=\frac{4\sqrt{10}}{-0.04}
=\frac{\sqrt{10}}{-0.01}
$